Matrix Cofactors: A Step-by-Step Guide

by Alex Johnson 39 views

Are you diving into the world of linear algebra and encountering those mysterious "cofactors"? Don't worry, you're not alone! Calculating cofactors for a matrix might seem a bit daunting at first, but with a clear understanding of the process, it becomes quite manageable. Let's break down how to find the cofactors for each row of a given matrix, using A=[1223−611−81372115]A=\left[\begin{array}{ccc} 12 & 23 & -6 \\ 11 & -8 & 13 \\ 7 & 21 & 15 \end{array}\right] as our example.

Understanding Cofactors

Before we get our hands dirty with calculations, let's quickly recap what a cofactor is. In essence, a cofactor is a specific number associated with each element in a matrix. It's a crucial component in several matrix operations, most notably in finding the determinant and the inverse of a matrix. Each cofactor, denoted as CijC_{ij}, is calculated by multiplying the minor of the element at position (i,j)(i, j) by (−1)i+j(-1)^{i+j}. The minor, in turn, is the determinant of the submatrix formed by removing the ii-th row and jj-th column from the original matrix.

So, to find a cofactor CijC_{ij}, we first need to identify the element aija_{ij} in the matrix. Then, we eliminate the row and column that element belongs to, creating a smaller matrix. We calculate the determinant of this smaller matrix – that's our minor. Finally, we multiply this minor by either 1 or -1, depending on the sum of the row and column indices (i+ji+j). If i+ji+j is even, we multiply by 1 (so the cofactor equals the minor). If i+ji+j is odd, we multiply by -1 (so the cofactor is the negative of the minor).

Calculating Cofactors for the First Row

Let's start with the first row of matrix AA. Our matrix is A=[1223−611−81372115]A=\left[\begin{array}{ccc} 12 & 23 & -6 \\ 11 & -8 & 13 \\ 7 & 21 & 15 \end{array}\right]. The elements in the first row are a11=12a_{11}=12, a12=23a_{12}=23, and a13=−6a_{13}=-6. We need to calculate the cofactors C11C_{11}, C12C_{12}, and C13C_{13}.

  • For a11=12a_{11} = 12 (position (1,1)): The minor M11M_{11} is the determinant of the submatrix formed by removing the first row and first column: ∣−8132115∣\left|\begin{array}{cc} -8 & 13 \\ 21 & 15 \end{array}\right|. M11=(−8×15)−(13×21)=−120−273=−393M_{11} = (-8 \times 15) - (13 \times 21) = -120 - 273 = -393. The cofactor C11=(−1)1+1×M11=(1)×(−393)=-393C_{11} = (-1)^{1+1} \times M_{11} = (1) \times (-393) = \textbf{-393}.

  • For a12=23a_{12} = 23 (position (1,2)): The minor M12M_{12} is the determinant of the submatrix formed by removing the first row and second column: ∣1113715∣\left|\begin{array}{cc} 11 & 13 \\ 7 & 15 \end{array}\right|. M12=(11×15)−(13×7)=165−91=74M_{12} = (11 \times 15) - (13 \times 7) = 165 - 91 = 74. The cofactor C12=(−1)1+2×M12=(−1)×74=-74C_{12} = (-1)^{1+2} \times M_{12} = (-1) \times 74 = \textbf{-74}.

  • For a13=−6a_{13} = -6 (position (1,3)): The minor M13M_{13} is the determinant of the submatrix formed by removing the first row and third column: ∣11−8721∣\left|\begin{array}{cc} 11 & -8 \\ 7 & 21 \end{array}\right|. M13=(11×21)−(−8×7)=231−(−56)=231+56=287M_{13} = (11 \times 21) - (-8 \times 7) = 231 - (-56) = 231 + 56 = 287. The cofactor C13=(−1)1+3×M13=(1)×287=287C_{13} = (-1)^{1+3} \times M_{13} = (1) \times 287 = \textbf{287}.

So, the cofactors of the first-row entries are -393, -74, and 287.

Calculating Cofactors for the Second Row

Now, let's move on to the second row of matrix AA. The elements here are a21=11a_{21}=11, a22=−8a_{22}=-8, and a23=13a_{23}=13. We need to find C21C_{21}, C22C_{22}, and C23C_{23}. Remember, the sign changes based on the sum of the row and column indices.

  • For a21=11a_{21} = 11 (position (2,1)): The minor M21M_{21} is the determinant of the submatrix formed by removing the second row and first column: ∣23−62115∣\left|\begin{array}{cc} 23 & -6 \\ 21 & 15 \end{array}\right|. M21=(23×15)−(−6×21)=345−(−126)=345+126=471M_{21} = (23 \times 15) - (-6 \times 21) = 345 - (-126) = 345 + 126 = 471. The cofactor C21=(−1)2+1×M21=(−1)×471=-471C_{21} = (-1)^{2+1} \times M_{21} = (-1) \times 471 = \textbf{-471}.

  • For a22=−8a_{22} = -8 (position (2,2)): The minor M22M_{22} is the determinant of the submatrix formed by removing the second row and second column: ∣12−6715∣\left|\begin{array}{cc} 12 & -6 \\ 7 & 15 \end{array}\right|. M22=(12×15)−(−6×7)=180−(−42)=180+42=222M_{22} = (12 \times 15) - (-6 \times 7) = 180 - (-42) = 180 + 42 = 222. The cofactor C22=(−1)2+2×M22=(1)×222=222C_{22} = (-1)^{2+2} \times M_{22} = (1) \times 222 = \textbf{222}.

  • For a23=13a_{23} = 13 (position (2,3)): The minor M23M_{23} is the determinant of the submatrix formed by removing the second row and third column: ∣1223721∣\left|\begin{array}{cc} 12 & 23 \\ 7 & 21 \end{array}\right|. M23=(12×21)−(23×7)=252−161=91M_{23} = (12 \times 21) - (23 \times 7) = 252 - 161 = 91. The cofactor C23=(−1)2+3×M23=(−1)×91=-91C_{23} = (-1)^{2+3} \times M_{23} = (-1) \times 91 = \textbf{-91}.

Therefore, the cofactors of the second-row entries are -471, 222, and -91.

Calculating Cofactors for the Third Row

Finally, let's tackle the third row of matrix AA. The elements are a31=7a_{31}=7, a32=21a_{32}=21, and a33=15a_{33}=15. We need to compute C31C_{31}, C32C_{32}, and C33C_{33}.

  • For a31=7a_{31} = 7 (position (3,1)): The minor M31M_{31} is the determinant of the submatrix formed by removing the third row and first column: ∣23−6−813∣\left|\begin{array}{cc} 23 & -6 \\ -8 & 13 \end{array}\right|. M31=(23×13)−(−6×−8)=299−48=251M_{31} = (23 \times 13) - (-6 \times -8) = 299 - 48 = 251. The cofactor C31=(−1)3+1×M31=(1)×251=251C_{31} = (-1)^{3+1} \times M_{31} = (1) \times 251 = \textbf{251}.

  • For a32=21a_{32} = 21 (position (3,2)): The minor M32M_{32} is the determinant of the submatrix formed by removing the third row and second column: ∣12−61113∣\left|\begin{array}{cc} 12 & -6 \\ 11 & 13 \end{array}\right|. M32=(12×13)−(−6×11)=156−(−66)=156+66=222M_{32} = (12 \times 13) - (-6 \times 11) = 156 - (-66) = 156 + 66 = 222. The cofactor C32=(−1)3+2×M32=(−1)×222=-222C_{32} = (-1)^{3+2} \times M_{32} = (-1) \times 222 = \textbf{-222}.

  • For a33=15a_{33} = 15 (position (3,3)): The minor M33M_{33} is the determinant of the submatrix formed by removing the third row and third column: ∣122311−8∣\left|\begin{array}{cc} 12 & 23 \\ 11 & -8 \end{array}\right|. M33=(12×−8)−(23×11)=−96−253=−349M_{33} = (12 \times -8) - (23 \times 11) = -96 - 253 = -349. The cofactor C33=(−1)3+3×M33=(1)×(−349)=-349C_{33} = (-1)^{3+3} \times M_{33} = (1) \times (-349) = \textbf{-349}.

Therefore, the cofactors of the third-row entries are 251, -222, and -349.

Conclusion

We've successfully calculated all the cofactors for each row of matrix AA! To summarize:

  • The cofactors of the first-row entries are -393, -74, and 287.
  • The cofactors of the second-row entries are -471, 222, and -91.
  • The cofactors of the third-row entries are 251, -222, and -349.

Understanding how to compute cofactors is a fundamental skill in linear algebra. It not only helps in finding determinants and inverses but also lays the groundwork for more advanced concepts. Keep practicing these calculations, and you'll soon master them!

For further exploration and to deepen your understanding of matrix operations, you can visit Khan Academy's comprehensive section on linear algebra. They offer excellent resources and tutorials that can help you solidify your knowledge.