Solving Cube Root Equations: A Step-by-Step Guide

by Alex Johnson 50 views

Cube root equations can seem daunting at first glance, but with a systematic approach, they become quite manageable. In this article, we will walk through the process of solving the equation 5xβˆ’73βˆ’2=0\sqrt[3]{5x - 7} - 2 = 0 step-by-step, ensuring you understand each stage and can apply the same method to similar problems. Our focus will be on clarity and providing a comprehensive understanding, so you’ll not only get the answer but also grasp the underlying principles.

Understanding Cube Root Equations

Before diving into the solution, let's briefly discuss what cube root equations are and why they might seem tricky. A cube root equation is an equation where the variable is under a cube root (3\sqrt[3]{ }). These equations fall under the broader category of radical equations, which involve radicals (roots). The key to solving these equations is to isolate the radical term and then eliminate the root by raising both sides of the equation to the appropriate power. This process can sometimes introduce extraneous solutions, so it’s crucial to check our final answers. Understanding this basic concept is crucial for tackling more complex problems later on. The importance of checking solutions cannot be overstated, as it ensures accuracy and avoids common pitfalls.

Step-by-Step Solution for 5xβˆ’73βˆ’2=0\sqrt[3]{5x - 7} - 2 = 0

Now, let's tackle the equation at hand: 5xβˆ’73βˆ’2=0\sqrt[3]{5x - 7} - 2 = 0. We'll break down the solution into easily digestible steps.

Step 1: Isolate the Cube Root

The first step in solving any radical equation is to isolate the radical term. In our equation, 5xβˆ’73βˆ’2=0\sqrt[3]{5x - 7} - 2 = 0, the cube root term is 5xβˆ’73\sqrt[3]{5x - 7}. To isolate it, we need to get rid of the "- 2". We can do this by adding 2 to both sides of the equation:

5xβˆ’73βˆ’2+2=0+2\sqrt[3]{5x - 7} - 2 + 2 = 0 + 2

This simplifies to:

5xβˆ’73=2\sqrt[3]{5x - 7} = 2

Now we have the cube root term isolated on one side of the equation. This step is fundamental because it sets us up for the next stage, where we'll eliminate the cube root. The ability to isolate the radical is a skill that will be used repeatedly in more advanced mathematical contexts.

Step 2: Eliminate the Cube Root

With the cube root isolated, our next goal is to eliminate it. To do this, we raise both sides of the equation to the power of 3 (since we're dealing with a cube root). This is based on the principle that (a3)3=a(\sqrt[3]{a})^3 = a. So, applying this to our equation:

(5xβˆ’73)3=23(\sqrt[3]{5x - 7})^3 = 2^3

This simplifies to:

5xβˆ’7=85x - 7 = 8

By raising both sides to the power of 3, we've successfully removed the cube root, transforming the equation into a simple linear equation. This step showcases the power of inverse operations in simplifying mathematical expressions.

Step 3: Solve the Linear Equation

Now that we've eliminated the cube root, we are left with a basic linear equation: 5xβˆ’7=85x - 7 = 8. To solve for xx, we need to isolate xx on one side of the equation. First, we add 7 to both sides:

5xβˆ’7+7=8+75x - 7 + 7 = 8 + 7

This simplifies to:

5x=155x = 15

Next, we divide both sides by 5:

5x5=155\frac{5x}{5} = \frac{15}{5}

This gives us:

x=3x = 3

So, we've found a potential solution: x=3x = 3. This step highlights the importance of algebraic manipulation in solving equations. The systematic approach to solving linear equations is a cornerstone of mathematical problem-solving.

Step 4: Check the Solution

As mentioned earlier, when dealing with radical equations, it’s crucial to check our solution to ensure it’s not extraneous. An extraneous solution is a value that satisfies the transformed equation but not the original equation. To check our solution, we substitute x=3x = 3 back into the original equation:

5(3)βˆ’73βˆ’2=0\sqrt[3]{5(3) - 7} - 2 = 0

Simplify inside the cube root:

15βˆ’73βˆ’2=0\sqrt[3]{15 - 7} - 2 = 0

83βˆ’2=0\sqrt[3]{8} - 2 = 0

The cube root of 8 is 2:

2βˆ’2=02 - 2 = 0

0=00 = 0

Since the equation holds true, x=3x = 3 is indeed a valid solution. This step underscores the critical nature of verifying solutions in the context of radical equations. The process of verification helps prevent errors and ensures the correctness of the final answer.

Final Answer

Therefore, the solution to the equation 5xβˆ’73βˆ’2=0\sqrt[3]{5x - 7} - 2 = 0 is x=3x = 3. We arrived at this solution by systematically isolating the cube root, eliminating it by cubing both sides, solving the resulting linear equation, and finally, verifying our solution.

Common Mistakes to Avoid

Solving cube root equations can be straightforward if you follow the steps carefully. However, there are common mistakes that students often make. Being aware of these pitfalls can help you avoid them.

Forgetting to Isolate the Radical

One of the most common mistakes is not isolating the radical term before raising both sides to a power. If you have other terms on the same side as the radical, raising both sides to a power will become much more complicated and likely lead to errors. Always make sure the radical term is by itself on one side of the equation before proceeding.

Incorrectly Applying the Power

Another mistake is incorrectly applying the power when eliminating the cube root. Remember that you need to raise both sides of the entire equation to the power of 3. Students sometimes only raise the terms under the radical to the power, which is incorrect.

Neglecting to Check for Extraneous Solutions

As we’ve emphasized, checking for extraneous solutions is vital. Failing to do so can lead you to include incorrect answers. Always substitute your solution back into the original equation to verify its validity. This step is often overlooked but is essential for accuracy.

Arithmetic Errors

Simple arithmetic errors can also lead to incorrect solutions. Whether it's adding, subtracting, multiplying, or dividing, ensure you double-check your calculations at each step. Even a small mistake can throw off the entire solution.

Practice Problems

To solidify your understanding, here are a few practice problems you can try:

  1. 2x+13βˆ’3=0\sqrt[3]{2x + 1} - 3 = 0
  2. 4xβˆ’53+1=0\sqrt[3]{4x - 5} + 1 = 0
  3. 2x+63=42\sqrt[3]{x + 6} = 4

Work through these problems using the steps we’ve outlined. Remember to isolate the radical, eliminate the cube root, solve the linear equation, and check your solutions. Practice is the key to mastering these types of equations.

Conclusion

Solving cube root equations involves isolating the radical, eliminating it by raising both sides to the appropriate power, solving the resulting equation, and verifying the solution. By following these steps carefully and avoiding common mistakes, you can confidently solve these types of equations. Remember, the key to success is practice and a systematic approach. Understanding the underlying principles and being meticulous with each step will make the process much smoother.

For further learning and practice on radical equations, you can explore resources like Khan Academy, which offers comprehensive lessons and practice exercises.